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September 20, 2014

September 20, 2014

Posted by **Desiree** on Monday, March 19, 2012 at 10:22pm.

A gas occupies 340mL at 273 K and 610 torr. What final temperature would be required to increase the pressure to 1 atm, the volume being held constant?

P1/T1 = P2/T2

T2 = (T1*P2)/ P1

1 atm = 760 torr

So,

T2 = (273 K * 760 torr)/610 torr

T2 = 340 K

- Chemistry -
**DrBob222**, Monday, March 19, 2012 at 10:26pm340 K is correct.

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