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calculus

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Let f (x) = x^2 + 5x-14. Find the open intervals on which f is concave up (down). Then determine the xcoordinates of all inflection points of f

1. f is concave up on the intervals
2. f is concave down on the intervals
3. The inflection points occur at x

  • calculus -

    f=x^2+5x-14
    f '=2x+5
    f ''=2

    since f'' > 0, always concave up (I mean, come on, it's a parabola!)

    so, no inflections
    this should have been a no-brainer

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