Posted by **Mandy** on Monday, March 19, 2012 at 2:53pm.

Let f (x) = x^2 + 5x-14. Find the open intervals on which f is concave up (down). Then determine the xcoordinates of all inflection points of f

1. f is concave up on the intervals

2. f is concave down on the intervals

3. The inflection points occur at x

- calculus -
**Steve**, Monday, March 19, 2012 at 3:57pm
f=x^2+5x-14

f '=2x+5

f ''=2

since f'' > 0, always concave up (I mean, come on, it's a parabola!)

so, no inflections

this should have been a no-brainer

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