Posted by Tony on Monday, March 19, 2012 at 6:19am.
50/130 is the sine of the angle the string makes with the wall. That angle is therefore A = 22.6 degrees. (The string, wall and horizontal form a 5-12-13 right triangle)
Now write horizontal and vertical force balance equations and solve for P and T. (T is the tension)
The vertical equilibrium equation will be:
T cos22.6 = M g
so you can already solve for T.
The horizontal equilbrium equation is
T sin22.5 = P
You finish it.
Related Questions
AQA Mechanics (M1), Statics and forces, please hel - A particle of weight W is ...
M1 mechanics - A particle of mass 5 kg is being towed at a constant speed of 6 m...
College Physics - A charged particle is hanging from the side of a wall by means...
Physics - A solid bar of length L = 1.30 m has a mass m1 = 0.893 kg. The bar is...
physics helpppp - particle 1 of mass m1 = 0.29 kg slides rightward along an x ...
physics - particle 1 of mass m1 = 0.29 kg slides rightward along an x axis on a ...
physics help - particle 1 of mass m1 = 0.29 kg slides rightward along an x axis...
physics help - particle 1 of mass m1 = 0.29 kg slides rightward along an x axis ...
physics - A weight (with a mass of 71 kg) is suspended from a point near the ...
physics help!!! - particle 1 of mass m1 = 0.29 kg slides rightward along an x ...
For Further Reading