Posted by
**mel** on
.

I balanced

Li(s) + Cl2(g)= LiCl(s) to

2Li(s) + Cl2(g)= 2LiCl(s)

Now the question is, if you have 39.8g Li, how many moles of LiCl would you have?

I am stuck on this part. Any help would be appreciated.