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Physics

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You have a 2.00 kg block of lead. Lead melts at 327.5°C. CPb = 130.0 , and Hf for lead is 2.04 × 104 J/kg. Say you start at room temperature (25.0°C). How much heat must you transfer to melt all the lead?

  • Physics -

    heat= heataddedToIncreaseTemp+ heataddedToMelt
    = 2kg*CPb*(327.5-25)+2kg*Hf

  • Physics -

    327.5x25.0=302.5 T= 302.5C q=2.00kg(130.0 kqc) (302.5c) q=H&M
    Q=78,650J Q=2.04x10^4 j/kg (2.00g)=40,800J
    Q=119,450J „³ 119,000J

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