Posted by **Pat** on Sunday, March 18, 2012 at 7:22pm.

You have a 2.00 kg block of lead. Lead melts at 327.5°C. CPb = 130.0 , and Hf for lead is 2.04 × 104 J/kg. Say you start at room temperature (25.0°C). How much heat must you transfer to melt all the lead?

- Physics -
**bobpursley**, Sunday, March 18, 2012 at 7:43pm
heat= heataddedToIncreaseTemp+ heataddedToMelt

= 2kg*CPb*(327.5-25)+2kg*Hf

- Physics -
**Carlos Q**, Monday, March 24, 2014 at 6:34pm
327.5x25.0=302.5 T= 302.5C q=2.00kg(130.0 kqc) (302.5c) q=H&M

Q=78,650J Q=2.04x10^4 j/kg (2.00g)=40,800J

Q=119,450J 119,000J

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