Posted by Shamin on Sunday, March 18, 2012 at 4:19pm.
x=8, δ=0.03
x=μ+zδ
μ=x-zδ
You have to find the mean that makes the range of 0oz to 8oz equal to 0.99 or the 99th percentile (because everything above 8oz should occur only in 1% of the time).
You can look up the z-value for 0.99 in a Standard Normal Distribution table.
z=2.32
μ=8-2.32*0.03=7.93
You get a mean of 7.93oz.
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