Posted by Anonymous on .
FIND THE SLOP of line containing points(2,8) and (3,5)

algebra 
Neil,
3/5

algebra 
Bosnian,
Two point form of linear equation :
y  y 1 = ( y 2  y 1 ) * ( x  x 1 ) / ( x 2  x 1 )
Te slope is explicitly given as
m = ( y 2  y 1) / ( x 2  x 1 )
In this case :
x 1 =  2
x 2 = 3
y 1 = 8
y 2 = 5
m = ( y 2  y 1 ) / ( x 2  x 1 )
m = ( 5  8 ) / [ 3  (  2 ) ]
m =  3 / ( 3 + 2 )
m =  3 / 5 =  0.6