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A 67.0 kg person, standing on a diving board, dives straight down into the water. Just before striking the water, her speed is 5.50 m/s. At a time of 1.75 s after she enters the water, her speed is reduced to 1.10 m/s. What is the net average force (magnitude and direction) that acts on her when she is in the water?

uuhh.. F=ma?

  • Physics -

    Kinematic description of decelerated motion of the diver gives
    a = (Vo-V)/t = (5.5-1.1)/1.75 = 2.51 m/s^2.
    From Newton’s 2 law
    F = m•a = 67•2.51=168.5 N

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