Post a New Question


posted by .

2. An object is moving along the parabola y = 3x^2.
a) When it passes through the point (2, 12), its “horizontal” velocity is dx/dt= 3. What dt
is its “vertical” velocity at that instant?

b)If it travels in such away that dx/dt=3 for all t,then what happens to dy/dt as t→+∞?

c) If, however, it travels in such a way that dy/dt remains constant, then what happens
to dx/dt as t→+∞?

  • Calculus -

    well, since y=3x^2

    dy/dt = 6x dx/dt
    = 6*2*3 = 36

    since dx/dt remains constant, dy/dt gets ever faster as x gets larger.

    If, however,

    k = 6x dx/dt, then dx/dt gets ever slower as x gets larger

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question