Posted by **jessica** on Sunday, March 18, 2012 at 1:14pm.

2. An object is moving along the parabola y = 3x^2.

a) When it passes through the point (2, 12), its “horizontal” velocity is dx/dt= 3. What dt

is its “vertical” velocity at that instant?

b)If it travels in such away that dx/dt=3 for all t,then what happens to dy/dt as t→+∞?

￼￼￼￼

c) If, however, it travels in such a way that dy/dt remains constant, then what happens

￼to dx/dt as t→+∞?

- Calculus -
**Steve**, Sunday, March 18, 2012 at 6:01pm
well, since y=3x^2

dy/dt = 6x dx/dt

= 6*2*3 = 36

since dx/dt remains constant, dy/dt gets ever faster as x gets larger.

If, however,

k = 6x dx/dt, then dx/dt gets ever slower as x gets larger

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