Posted by smh on Sunday, March 18, 2012 at 12:19pm.
The friction force during the motion along the inclined plane is
F(fr)1 = kN = k•m•g•cosα.
The work of this force is
W1= k•m•g•cosα•s.
The law of conservation of energy gives
PE=KE+W1,
m•g•h = m•v^2/2 + k•m•g•cosα•s.
m•v^2/2 = m•g•h - k•m•g•cosα•s.
For the motion along the horizontal path
KE=W2,
m•v^2/2 = k•m•g•s1
s1= m•v^2/2• k•m•g
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