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September 23, 2014

September 23, 2014

Posted by **jose** on Sunday, March 18, 2012 at 8:46am.

- applied physics -
**drwls**, Sunday, March 18, 2012 at 8:52amLet the heights of the two stones above the ground be Y1 and Y2.

Y1 = 100 - 4.9 t^2 (the dropped stone)

Y2 = -4.9 t^2 + 50 t (the thrown-upward stone)

Now set Y1 = Y2 and solve for t.

The t^2 terms drop out and you get an easy linear equation to solve.

Enjoy!

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