Posted by Priyanka on Sunday, March 18, 2012 at 4:02am.
They want you to neglect friction between the boat and the water. With that assumption, the center of mass of the boat and woman remain in the same place, relative to the pier. When she stops walking, the boat stops moving.
Let X be the distance of the close end of the boat from the pier. Initially
X = Xi = 0.5 m. Afterwards, X = Xf. You want to know the value of Xf.
Initial CM location =
[148*3.5 + 44*6.5]/(148+44) = 4.188 m
Final CM location =
[148*(3+Xf) + 44*Xf]/192 = 4.188
Solve for Xf
804= 444 + 148 Xf + 44 Xf
360 = 192 Xf
Xf = 1.875 m
The boat ends up farther from the pier, although the woman ends up closer to it.
(b) The woman was initially 6.5 m from the pier and ended up 1.875 m away. She moved 4.625 m closer, relative to the pier.
Thank you Drwls! I really appreciate your help.
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