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November 26, 2014

November 26, 2014

Posted by **Adrianna** on Sunday, March 18, 2012 at 12:12am.

40°±360°k

140°±360°k

220°±360°k

320°±360°k

How do I find the right answer? I am like seriously stuck. I need help please.

- inverse trig HELP PLEASE!! -
**Reiny**, Sunday, March 18, 2012 at 8:46amset your calculator to degrees (the DRG key)

enter:

2ndF

sin

.6428

=

you should get 40.00...

since sinØ has a period of 360° , adding or subtracting multiples of 360° will produce the same answer

so 40° ± 360k would be the general solution

you might check with some arbitrary value of k

say k = 5

then 40 + 5(360) = 1840

sin 1840° = .64278 , close enough!

(on some calculators you have to enter the argument first,

e.g.

.6428

2ndF

sin

you will have to test your device.

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