February 20, 2017

Homework Help: Chemistry, please help!

Posted by Mason on Saturday, March 17, 2012 at 11:26pm.

The average human body contains 6.20 L of blood with a concentration of 2.40×10−5 M . If a person ingests 8.00 mL of 13.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?

According to the equation:
Fe2+ + 6CN- ->[Fe(CN)6]4-
kf = 4.21*10^45

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