Thursday
March 30, 2017

Post a New Question

Posted by on .

A diver jumps off a 10m diving board with an initial upward velocity of 5.0 m/s. What is the diver's velocity after 1.5 seconds?

  • Physics - ,

    Initially, the diver is moving upwards
    0 = Vo – gt,
    t = Vo/g ≈ 5/10 = 0.5 s.
    After 0.5 seconds of motion the diver is at the maximum height.
    Then the downward motion begins.
    After 1.5 - 0,5 = 1 second of motion the velocity of diver is
    v = g•t = 10•1= 10 m/s.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question