Posted by **Anthony** on Saturday, March 17, 2012 at 3:32pm.

A diver jumps off a 10m diving board with an initial upward velocity of 5.0 m/s. What is the diver's velocity after 1.5 seconds?

- Physics -
**Elena**, Saturday, March 17, 2012 at 4:18pm
Initially, the diver is moving upwards

0 = Vo – gt,

t = Vo/g ≈ 5/10 = 0.5 s.

After 0.5 seconds of motion the diver is at the maximum height.

Then the downward motion begins.

After 1.5 - 0,5 = 1 second of motion the velocity of diver is

v = g•t = 10•1= 10 m/s.

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