Posted by Angela on .
A 42kg girl is bouncing on a trampoline. During a certain interval after leaving the surface of the trampoline, her kinetic energy decreases to 220 J from 460 J. How high does she rise during this interval? Neglect air resistance.
Just wondering how to solve this.

College Physics 
drwls,
The kinetic energy decrease (240 J) equals her potential energy increase: (M*g*deltaY)
Delta Y is her increase in elevation during that time, which is
240J/(M*g) = 0.583 m