Posted by **Katie** on Friday, March 16, 2012 at 10:31pm.

A ball of radius 0.211 m rolls along a horizontal table top with a constant linear speed of 3.41 m/s. The ball rolls off the edge and falls a vertical distance of 2.27 m before hitting the floor. What is the angular displacement of the ball while the ball is in the air?

- physics -
**Elena**, Saturday, March 17, 2012 at 12:38pm
An angular velocity of the ball is

ω = v/R=3.41/0.211=16.16 rad/s.

The ball is falling down, therefore,

h=gt^2/2.

Then

t=sqr(2h/g)=sqr(2•2.27/9.8)=0.68 s.

The angular displacement of the ball is

φ = ω •t =16.16•0.68 = 11 rad.

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