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March 30, 2015

March 30, 2015

Posted by **dmkp** on Friday, March 16, 2012 at 6:12am.

a) calculate the kinetic energy of the ball as it is released

b)calculate the maximum height reached by the ball

c) state the velocity of the ball when it returns to its starting position

d)state which conservation principle you used to obtain your answers to questions (b) and (C)

e) if the ball hit the ground 2 metres below the point from which it was thrown, calculate the impulse and impulse force of the 1 millisecond impact.

- kinetics -
**Henry**, Saturday, March 17, 2012 at 4:37pma. KE = 0.5m*V^2 = 0.1*(20)^2 = 40 Joules.

b. hmax = (V^2-Vo^2) / 2g.

hmax = (0-(20)^2) / -19.6 = 20.41 m.

c. V = Vo = 20 m/s.

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