a particle element has 2 isotopes in natural occuring mixture 47.8%of mixture is isotope weighing 150.9196 amu. The other weighs 152.9209amu. Calculate the atomic mass for this element show work
152.9209(fractional abundance) + (150.9196(fractional abunance) = ?
151.9643
To calculate the atomic mass of the element with two isotopes, we need to consider the abundance (percentage) of each isotope and the mass of each isotope.
Given:
- Abundance of the first isotope: 47.8%
- Mass of the first isotope: 150.9196 amu
- Mass of the second isotope: 152.9209 amu
To calculate the atomic mass, we can use the following formula:
Atomic mass = (Abundance1 * Mass1) + (Abundance2 * Mass2)
Now let's substitute the given values into the formula and calculate the atomic mass:
Atomic mass = (0.478 * 150.9196 amu) + (0.522 * 152.9209 amu)
Calculating the above expression:
Atomic mass = 72.2170928 amu + 79.8024168 amu
Atomic mass = 152.0195096 amu
Therefore, the atomic mass of this element is approximately 152.0195 amu.