Posted by Mike on .
Calculate the pH after 0.011 mol NaOH is added to 1.00 L of each of the four solutions.
a) 0.100 M propanoic acid (HC3H5O2, Ka= 1.3 10-5)
b) 0.100 M sodium propanoate (NaC3H5O2)
d) 0.100 M HC3H5O2 and 0.100 M NaC3H5O2
Do you have any thoughts on these at all? First you must recognize what kind of acids/bases are involved.