Posted by **Sandra g** on Thursday, March 15, 2012 at 9:30pm.

at noon A is 150 km west of a ship B .Ship A is sailling east at 35 km/h , and ship B is sailling north at 25 km/h. How fast is the distance between the ships changing at 4 pm ?

- Calculus -
**Steve**, Friday, March 16, 2012 at 11:44am
the distance between the ships at time t is

d^2 = (150-35t)^2 + (25t)^2

at t=4,

d^2 = (150-140)^2 + (100)^2 = 100 + 10000 = 10100, so d=100.5

2d dd/dt = 2(150-35t)(-35) + 2(25t)(25)

at t=4,

201 dd/dt = -700 + 5000

dd/dt = 21.39km/h

## Answer This Question

## Related Questions

- calculus - At noon, ship A is 150 km west of ship B. Ship A is sailing east at ...
- calculus - At noon, ship A is 150 km west of ship B. Ship A is sailing east at ...
- Calculus - At noon, ship A is 150 km west of ship B. Ship A is sailing east at ...
- calc - At noon, ship A is 150 km west of ship B. Ship A is sailing east at 35 km...
- calc - At noon, ship A is 150 km west of ship B. Ship A is sailing east at 35 km...
- Calculus - At noon, ship A is 180 km west of ship B. Ship A is sailing east at ...
- calculus - At noon, ship A is 110 km west of ship B. Ship A is sailing east at ...
- calc - At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km...
- calculus - At noon, Ship A is 100 km west of ship B. Ship A travels south at 35 ...
- Calculus - "At 9am ship A is 50 km east of ship B. Ship A is sailing north at ...

More Related Questions