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March 31, 2015

March 31, 2015

Posted by **Amanda** on Thursday, March 15, 2012 at 8:49pm.

- Finite Math -
**Reiny**, Thursday, March 15, 2012 at 9:26pmLooks like you want us to do an assignment for you.

I will do this last one, but then you must show us that you have some kind of method for doing these.

number of possible committees

= C(22,6) = 74613

number with NO junior partners = C(13,6) = 1716

so the number with at least one junior = 74613-1716 = 72897

prob of at least one junior = 72897/74613 = 6627/6783= 2209/2261 = appr .977

- Finite Math -
**Amanda**, Friday, March 16, 2012 at 1:26ami want help understanding how to solve the problems, not just the answers. I understand how to get the denominator, by getting the total and nCr the sample, but i cannot figure out the numerator when it comes to solving these probability problems.

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