A factory produces fuses, which are packaged in boxes of 26. Eight fuses are selected at random from each box for inspection. The box is rejected if at least one of these eight fuses is defective. What is the probability that a box containing twelve defective fuses will be rejected?
Finite Math - Amanda, Friday, March 16, 2012 at 2:42am
C (14,8) = 3003
C (26,8) = 1562275
1562275 - 3003 = 1559272
ANSWER= 1559272/1562275 (cannot be simplified)