Posted by Kim on .
sketch the region bounded by the graphs of f(y)=(y/Squareroot of(16y^2)), g(y)=0, y=3 and find the area of the region.

Math 
Reiny,
x = y/√(16y^2)
as seen on Wolfram
http://www.wolframalpha.com/input/?i=x+%3D+y%2F√%2816y%5E2%29
taking horizontal slices
Area = ∫( y/(16y^2)^(1/2) dy from 0 to 3
=  (16y^2)^(1/2)  from 0 to 3
= (169)^(1/2)  (16^(1/2))
= √7 + 4
= 4√7 = appr 1.35