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Posted by on Thursday, March 15, 2012 at 6:23pm.

Q. Find the minimum value of Q=x^2y subject to the constraint 2x^2+4xy=294.


Its the derivative method.

  • Calculus- please help - , Thursday, March 15, 2012 at 8:46pm

    Hints:
    Here you have two variables, and one constraint. From the constraint, y can be solved in terms of x. This value of y can then be substituted into Q to make Q a function of Q=Q(x), whose minimum value can be calculated by differentiation.
    I get x=±7√2.
    Check each to make sure it is a minimum or maximum.

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