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March 31, 2015

March 31, 2015

Posted by **james** on Thursday, March 15, 2012 at 6:15pm.

a) log4 (1/8)

B)10^(-10log3)<---superscript in brackets

c.2log3<-----subscript.9

d.log3<---subscript.3^2x

- math -
**Steve**, Friday, March 16, 2012 at 10:36am4 = 2^2, so 2 = 4^(1/2)

1/8 = 1/2^3 = 2^-3 = (4^1/2)^-3 = 4^(-3/2)

so, log4(1/8) = -3/2

10^(-10log3) = 10^(-log 3^10) = 10^(log 3^(-10)) = 3^(-10)

log3(9) = 2

2log3(.9) = log3(.9^2) = log3(.81)

log3(.81) = log3(81) - log3(100) = 4-log3(100)

recall that logb(b^x) = x

log3(3^2x) = 2x

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