Posted by
**Hannah** on
.

Using this data,

2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3

NO2(g) == NO(g) + ½ O2(g) Kc = 3.93

calculate a value for Kc for the reaction,

NOCl (g) + ½ O2 (g) == NO2 (g) + ½ Cl2 (g)

So I understand that

2NO + Cl2 + 1/2O2 = NO2 + 1/2 Cl2 but I do not understand how you use the Kc values that are given since this equation is slightly different. 2NO + Cl2 is in the first equation but then the 1/2O2 is in the second equation and they both have different Kc values.