Homework Help: Chemistry(Please respond, thank you!)

Posted by Hannah on Thursday, March 15, 2012 at 1:54pm.

Using this data,
2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3

NO2(g) == NO(g) + ½ O2(g) Kc = 3.93

calculate a value for Kc for the reaction,

NOCl (g) + ½ O2 (g) == NO2 (g) + ½ Cl2 (g)

So I understand that
2NO + Cl2 + 1/2O2 = NO2 + 1/2 Cl2 but I do not understand how you use the Kc values that are given since this equation is slightly different. 2NO + Cl2 is in the first equation but then the 1/2O2 is in the second equation and they both have different Kc values.

No one has answered this question yet.

Answer this Question

Related Questions

Chemistry(Please help, thank you!) - Using this data, 2 NO(g) + Cl2(g) == 2 NOCl...
chemistry - Using this data, 2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3 NO2(...
Chemistry - Using this data, 2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3 NO2(...
Chemistry - Using this data, 2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3 NO2(...
chemistry - Using this data, 2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3 NO2(...
chemistry - Using this data, 2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3 NO2(...
College Chemistry - Determine Kc at 298 K for the reaction 1/2 N2(g0 + 1/2 O2(g...
Chemistry - 0.500 moles of NOCl is placed in a 1.00L vessel at 700K,and after ...
chemistry - I have been at this question for at least three hours now. Consider ...
Chem II - 2.5 mol NOCl(g) was placed in a 2.50 L reaction vessel at 400 degrees ...

For Further Reading

First Name:
School Subject:
Answer: