you are right the question is exactly like this... can you help me for this question.... thanks

Write a MAIN function and a FUNCTION to compute the sum of the below series.

((-1)^(n+1)*n!)/(n^n) (from n=1 to infinity)

Within the MAIN function:
. Read a variable EPSILON of type DOUBLE (desired accuracy) from
the standard input.
EPSILON is an extremely small positive number which can be anything
between 1E-06 (10^(-6)) and 1E-12 (10^(-12)).
. EPSILON value will be passed to the FUNCTION as an argument.
Within the FUNCTION:
. In a do-while loop:
. Continue adding up the terms until |Sn+1 - Sn| < EPSILON.
. Sn is the sum of the first n-terms.
. Sn+1 is the sum of the first (n+1)-terms.
When the desired accuracy EPSILON is reached print the SUM and the number
of TERMS added to the sum.

Your teacher's instruction ressemble very much a pseudocode. Just transcribe and start coding.

Can you propose a pseudocode, or actual coding so that we have a starting point?

sir. ý don't understand anything.. ý need answer in c program. and the program should to run...

Here's a sample C-code template for you to start with.

C++ would be slightly different
You just have to add in your own code.
If you have no idea where to start, review your teacher's notes, or do the best you can.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{

printf("Hello World!\n");
}

ý am sorry but. you can't do all this question??? I DON'T KNOW THÝS PROGRAM... :S:S

I have done this whole program. I have even showed you the results of the (wrong) series to show that the question was wrong.

However, I am sorry that I should not post my program. I can help you get there, to make sure it works, if you show efforts on your part. Your teacher gave you this assignment so that you can learn. If you take my program ans submit as your own work, it would be plagiary, and worse, you haven't learned anything.

If you want to achieve anything close to writing a program, there is no other way than to write it and learn from mistakes. This is why compilers are there to check your program for obvious mistakes. We're here to help you if you cannot figure out the mistakes.

Sure! I can help you with this question.

To solve this problem, you will need to write a main function and another function to compute the sum of the given series.

Here is an outline of the steps to follow:

1. Write the main function:
- Read the value of EPSILON from the standard input. (EPSILON is a double representing the desired accuracy.)
- Pass the value of EPSILON as an argument to the second function.

2. Write the second function:
- Initialize the variables `sum` (to keep track of the sum) and `term` (to store the value of each term in the series).
- Start a do-while loop to iteratively compute the sum until the desired accuracy is reached.
- Inside the loop, calculate and add each term to the sum according to the given series.
- Compute the absolute difference between the sum after adding the current term and the sum before adding the current term.
- Check if the absolute difference is less than EPSILON.
- If the condition is not met, continue the loop; otherwise, exit the loop.
- Print the final sum and the number of terms added to the sum.

Now, let's see the implementation in C++:

```cpp
#include <iostream>
#include <cmath>
using namespace std;

// Function to compute the sum of the series
void computeSum(double epsilon) {
double sum = 0.0;
double term = 0.0;
int n = 0;

do {
n++;
int sign = pow(-1, n + 1);
int factorial = 1;
int power = pow(n, n);

// Calculate the current term
for (int i = 1; i <= n; i++) {
factorial *= i;
}
term = (sign * factorial) / power;

// Add the term to the sum
sum += term;

} while (abs(term) >= epsilon);

cout << "Sum: " << sum << endl;
cout << "Number of terms added: " << n << endl;
}

int main() {
double epsilon;

// Read the value of EPSILON from input
cout << "Enter the desired accuracy (EPSILON): ";
cin >> epsilon;

// Call the function to compute the sum
computeSum(epsilon);

return 0;
}
```

In this program, we declare the `computeSum` function to calculate the sum of the series. Then, we implement the do-while loop to continue adding terms until the desired accuracy (`epsilon`) is reached.

Finally, we call the `computeSum` function within the `main` function, after reading the value of `EPSILON` from the standard input.

I hope this helps! Let me know if you have any further questions.