Tuesday
March 28, 2017

Post a New Question

Posted by on .

For the system CaO(s) + CO2(g) = CaCO3(s), I added 1.00 mol of CaO(s) to 1.00L of 0.500M CO2(g) at 200 oC. At equilibrium the [CO2] = 0.150M. What is the value of Kp for this reaction?

Kp would = CaCO3/(CaO)(CO2)

I do not know what to do with the 0.500M and 1.00mol.



Chemistry(Please help) - DrBob222, Wednesday, March 14, 2012 at 10:32pm
First you need to work on the Kp expression. SOLIDS aren't used (pure liquids aren't either) so the expression is 1/pCO2 = Kp.
The problem tells you that AT EQUILIBRIUM [CO2] = 0.150M.
I would calculate Kc from Kc = 1/([CO2]
then convert to Kp by Kp = Kc(RT)Dn



So I did 1/0.150 and got 6.66 so now I use this with RT. I am not sure what R is? Kp=6.66(200C + 273)(R)??

  • Chemistry(Please respond, thank you!) - ,

    I thought one of the first constants one learned in chemistry from the PV = nRT equation was R. R = 0.08206 L*atm/mol*K.

  • Chemistry(Please respond, thank you!) - ,

    ok so 6.66(473K)(0.08206) = 258.5 which would be 2.59 which is one of the answer choices. Does this seem correct??

  • Chemistry(Please respond, thank you!) - ,

    the R will be molecular mass of the equation of the reaction

  • Chemistry(Please respond, thank you!) - ,

    I don't think so.
    Kp = Kc(RT)Dn.
    You have Kc, R, T but you don't have delta n anywhere in the equation. Also, note that it is NOT R*Tdelta n but (RT)delta n

  • Chemistry(Please respond, thank you!) - ,

    Hannah, I understand that you are having trouble with the homework but academic dishonesty is not the answer. I will be flagging your academic transcripts by the end of today, please come speak with me as soon as you can, maybe we can work something out.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question