Posted by Krista on Thursday, March 15, 2012 at 12:36pm.
wf^2=wi^2+2A*displacement
A= -wi^2/2(1.5rev)
if initial speed is the doubled, then w^2 term in the numerator is x4, so rev must be x4 to keep A constant.
so 4x1.5=6rev
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