Posted by Nicole on Thursday, March 15, 2012 at 12:21pm.
sixty degres measured how?
Measured to the horizontal
Throw*
Then the vertical velocity initial is Vsin60.
At the top, vertical velocity is zero.
Vtop=Vivertial-gt
so time to top= Vivertial/g=Vsin60 /g
then solve for V
Now how far: You have to find vertical time in air.
hf=hi+Vivertical*t-1/2 g t^2
0=23+Vsin60* t-1/2 g t^2
solve for t, time in air. Use the quadratic formula.
Now distance: distance= Vhoriz*timeinair
where vhoriz= Vcos60
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