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March 28, 2015

March 28, 2015

Posted by **Nicole** on Thursday, March 15, 2012 at 12:21pm.

(a) With what speed did you throw the rock?

(b) How far away from the bridge horizontally did the rock land?

- physics -
**bobpursley**, Thursday, March 15, 2012 at 12:24pmsixty degres measured how?

- physics -
**Nicole**, Thursday, March 15, 2012 at 12:29pmMeasured to the horizontal

Throw*

- physics -
**bobpursley**, Thursday, March 15, 2012 at 12:37pmThen the vertical velocity initial is Vsin60.

At the top, vertical velocity is zero.

Vtop=Vivertial-gt

so time to top= Vivertial/g=Vsin60 /g

then solve for V

Now how far: You have to find vertical time in air.

hf=hi+Vivertical*t-1/2 g t^2

0=23+Vsin60* t-1/2 g t^2

solve for t, time in air. Use the quadratic formula.

Now distance: distance= Vhoriz*timeinair

where vhoriz= Vcos60

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