Sunday

April 19, 2015

April 19, 2015

Posted by **Mooch** on Thursday, March 15, 2012 at 11:35am.

I've come as far as y = arccos ((arcsin(x))/pi), but I am not certain this is right.

- Calculus (Derivatives of Inverse Functions) -
**Steve**, Thursday, March 15, 2012 at 2:18pmyour expression for y is right. so,

Let u = 1/pi arcsinx

(arccos u)' = -1/sqrt(1-u^2) u'

= -1/sqrt(1-u^2) * 1/pi * 1/sqrt(1-x^2)

= - 1/sqrt(1- 1/pi^2 (arcsinx)^2) * 1/pi * 1/sqrt(1-x^2)

= - 1/[sqrt(pi^2 - (arcsinx)^2)*sqrt(1-x^2)]

yummm! gotta love it!

Calculus (Please check my work!) - Suppose that y = f(x) = x^2 - 4x + 4. Then on...

inverse - If f(x)=cosx + 3 how do I find f inverse(1)? Thanks y = cos(x) + 3 the...

Math - Suppose f(x) = sin(pi*cosx) On any interval where the inverse function y...

inverse functions - 1-3cos=sin squared You need to define the variables, such as...

Calc AB - Suppose that y = f(x) = x^2-4x+4 Then on any interval where the ...

Advanced Algebra - What is the inverse of each of the functions defined by the ...

Calculus 12th grade (double check my work please) - 1.)Find dy/dx when y= Ln (...

math - Eliminate the parameter (What does that mean?) and write a rectangular ...

Calculus - F(x) = 1-x and g(x) = 1/x These functions have the property that f = ...

Calculus III - Derivative of Inverse Trigonometric Functions f(x) = cos(arcsin(...