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March 28, 2017

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Find the following limits algebraically or explain why they don’t exist.

lim x->0 sin5x/2x
lim x->0 1-cosx/x
lim x->7 |x-7|/x-7
lim x->7 (/x+2)-3/x-7
lim h->0 (2+h)^3-8/h
lim t->0 1/t - 1/t^2+t

  • Calculus - ,

    a lot of your questions contain ambiguous typing
    e.g. the second last one probably says

    lim ( (2+h)^3 - 8)/h as h --> 0

    You could expand the top, or recognize it as a difference of cubes
    recall A^3 - B^3 = (A-B)(A^2 + AB + B^2)

    = lim [(2+h - 2)((2+h)^2 + 2(2+h) + 4) )/h , h--->0
    = lim (2+h)^2 + 2(2+h) + 4 , h--> 0
    = 4 + 4 + 4 = 12

    for the first one
    I will again assume you meant
    lim sin (5x) / (2x) , as x --> 0

    recall that lim sinØ/Ø = 1 as Ø -->0

    so let's "construct" this pattern
    multiply top and bottom by (5/2)
    so
    lim sin (5x) / (2x) , as x --> 0
    = lim (5/2)sin (5x)/( (2x)(5/2)
    = (5/2) lim sin (5x) / (5x) , as x--->0
    = (5/2)(1) = 5/2

    try some of the others now after checking on your typing using brackets.

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