Posted by Shihara on Thursday, March 15, 2012 at 8:10am.
since the lighthouse is 10 mi NE of the dock, it is 7.07mi east and 7.07 mi north. (legs of a 45-45-90 triangle)
Now, if the ship is 8 mi from the lighthouse, we have a new x-7.07-8 triangle, so x = 3.74.
Now, the distance from the dock to the ship is 7.07 - 3.74 = 3.33 mi.
At 12 mi/hr, that would take 3.33/12 = .277777 hours, or 16'40"
So, at 12:16:40 the ship is 8 mi from the lighthouse
Note: the ship will also be 8 miles from the lighthouse after it has passed it and is east of the lighthouse. From the above data, you can figure the second time with no trouble.
Related Questions
math - Howard leaves the dock and sails 2.5miles west He turns south and sails 3...
Pre-Calculus-Trig - A boat travels for 8 kilometers in a straight line from the ...
physics - An 88kg fisherman jumps from a dock into a 131kg rowboat at rest on ...
Mathamatics - A ship is due south of a lighthouse. It sails on a bearing of 72* ...
pre calc - Lighthouse B is 8 miles west of lighthouse A. A boat leaves A and ...
Algebra - If a boat leaves dock and travels 3 miles north, then travels 2.5 ...
Physics - Note: Take East as the positive direction. A(n) 86 kg fi...
Calculus Help Please - Ship A is traveling west at 40kkm/h and ship B is ...
Trig - A ship leaves its homeport and sails on a bearing of N28degrees10'E. ...
physics - an 84 kg fisherman jumps for a dock into a 122 kg rowboat at rest on ...
For Further Reading
