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35.00mL of 0.250M KOH solution is required to completely neutralize 10.50mL of H2SO4 solution. what is the molarity of the sulfuric acid solution
KOH(aq)+ H2SO4 -------> K2SO4(aq) +H2O(l

  • chemistry -

    2KOH(aq)+ H2SO4 -------> K2SO4(aq) +H2O(l)
    Note that I have balanced the equation.
    mols KOH = M x L = ?
    moles H2SO4 = mols KOH x 1/2
    M H2SO4 = mols H2SO4/L H2SO4

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