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April 21, 2014

April 21, 2014

Posted by **tharidu** on Thursday, March 15, 2012 at 1:56am.

- physics -
**Henry**, Friday, March 16, 2012 at 3:56pma. Perpendicular to and toward the frame and wall.

b. Opposite direction of normal force exerted by hand.

c. A = 90 - 40 = 50 Deg., CCW.

Fv = 5 + 6*sin50 = 9.60 N. = Normal.

Fn = Fap - u*Fv = 0.

6*cos(50) - u*9.6 = 0.

9.6u = 6*cos(50) = 3.86.

u = 3.86 / 9.6 = 0.402.

- physics -
**Henry**, Friday, March 16, 2012 at 4:16pmIf the picture was placed on the opposite wall, the angle would be:

A = 90 + 40 = 130 Deg.

The cosine would be negative and the

coefficdient of friction and force ot

friction would be in opposite direction.

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