Posted by mary on Thursday, March 15, 2012 at 1:39am.
Hello, please help me, I'm studying for a test. :)
I won't say the question because I'd like to figure it out myself or try first, but I'm looking for a simpler way to go about this.
I have to find the derivative of h(x)= (x)(x1)^1/3
I got: h'(x)= (x1)^1/3 + (1/3)(x)(x1)^2/3
I'm looking for a way to combine the two terms, but the cube roots are messing me up and I'm not completely sure how to go about it... been stuck on this for about an hour...
If any one can help me simplify h'(x) and, if you'd like, show me how, that would be amazing!
Thank you for your time.

calculusderivatives  Steve, Thursday, March 15, 2012 at 11:47am
Not much joy here. You could always factor out the (x1)^2/3 to get
(x1)^2/3 * (x1 + x/3)
= (x1)^2/3 * (4x/3 1)
Depending on what comes next, you may want to massage it some.

calculusderivatives  mary, Thursday, March 15, 2012 at 12:04pm
:D I'm so happy! Never thought to factor that out x) thank you!
Answer This Question
Related Questions
 calculusderivatives  Hello, please help me. I needed to find the derivative of...
 Lingusitics  Hello everyone!! For these six sentences, I have to explain what ...
 Calculus  Okay so I have a question on my assignment that says: You are given ...
 English  Native speakers  Hello! I am trying to figure out one of the most ...
 Math  Hi everyone, I would like some help with Math.. And I would like help ...
 US History  Hello! I have to do a project about a colony that became a state, ...
 MATH STUCK:(  I am having some difficulties factoring polynomials and I use ...
 reading  the reason the test questions and answers is up there because its all ...
 English  Hello. Please help me understand the sentence: "I took my picture" (...
 Business  Hi, I'm studying for a test on Desktop Publishing, and the question I...
More Related Questions