Homework Help: physics

Posted by nuwan on Thursday, March 15, 2012 at 12:58am.

The coefficient of static friction between a block and a horizontal floor is 0.40, while the coefficient of kinetic friction is 0.15. The mass of the block is 5.0 kg. A horizontal force is applied to the block and slowly increased. (a) What is the value of the applied horizontal force at the instant that the block starts to slide? (b) What is the net force on the block after it starts to slide?

physics - Henry, Friday, March 16, 2012 at 2:33pm
Wb = mg = 5kg * 9.8N/kg = 49 N. = Wt. of block.

Fb = 49N @ 0 Deg.
Fp = 49*sin(0) = 0 = Force parallel to
floor.
Fv = 49*cos(0) = 49 N. = Force perpendicular to floor.

a. Fn = Fap - Fp - 0.4Fv = 0.
Fap - 0 - 19.6 = 0.
Fap = 19.6 N.

b. Fn = Fap - Fp - 0.15Fv.
Fn = 19.6 - 0 - 7.35 = 12.25 N.

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