Post a New Question

Related rate

posted by on .

Use differentials to find the approximate change in the surface area when the radius of the sphere is increased from 10cm to 10.2cm.

I know A=4pir^2 and A' is 8pir but I'm not sure how to set it up from here. Can someone please show me all the steps involved? (This isn't HW, just a textbook question that I can't figure out, thanks!)

  • Related rate - ,

    Ha! I figured it out.

    dA=8pir dr
    r=10 , dr=10.2

    dA=8(10)(.2)pi
    dA=16pi (approx)

    check:
    A(10)=4(10)^2pi
    A(10)=400pi
    A(10.2)=4(10.2)^2pi
    A(10.2)=416.16

    A(10.2)-A(10)=16.16pi (exact)

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question