Homework Help: College Physics - Speed

Posted by Anonymous on Wednesday, March 14, 2012 at 9:03pm.

Traveling at a speed of 15.6 m/s, the driver of an automobile suddenly locks the wheels by slamming on the brakes. The coefficient of kinetic friction between the tires and the road is 0.730. What is the speed of the automobile after 1.25 s have elapsed? Ignore the effects of air resistance.

College Physics - Speed - bobpursley, Wednesday, March 14, 2012 at 9:06pm
Vf=Vi+at where a= forcefriction/mass= .730*mg/m= .730g
College Physics - Speed - Anonymous, Wednesday, March 14, 2012 at 9:15pm
I don't have mass so I can't use this formula :(
College Physics - Speed - bobpursley, Wednesday, March 14, 2012 at 9:16pm
good grief.

.730mg divided by m is .730g
College Physics - Speed - Anonymous, Wednesday, March 14, 2012 at 9:31pm
No matter how I use the formula you provided I do not get the correct answer of: 6.66 m/s.
College Physics - Speed - bobpursley, Wednesday, March 14, 2012 at 9:36pm
You may want to drop physics.
Put this into your google search window
15.6-.730*9.8*1.25=
which is
Vf-mu*g*1.25
College Physics - Speed - Anonymous, Wednesday, March 14, 2012 at 9:55pm
Thanks for your help bobpursley. However, your advise was unwarranted. Just because someone needs additional help understanding a concept doesn't mean they should "drop" out of a class. Jiskha is a learning environment for those seeking help to better understand ideas and concepts please remember that.

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