what is the solubility of X in mole/dm3 if 25cm of its saturated solution contains 4.0g of X.

4.0 g in 25 cc x (1000 cc/25 cc) = ?g/dm^3 but I don't know how many moles that is because you didn't supply a molar mass.

The answer to this question

To find the solubility of X in moles per dm^3, we need to use the given information that 25 cm^3 of the saturated solution contains 4.0 grams of X.

1. Start by converting the volume of the solution from cm^3 to dm^3. Since 1 dm^3 is equal to 1000 cm^3, we divide 25 cm^3 by 1000 to get 0.025 dm^3.

2. Next, we need to calculate the molarity of the solution. The molarity (M) of a solution is defined as the number of moles of solute per dm^3 of solution. We can use the formula:

Molarity (M) = moles of solute / volume of solution (in dm^3)

Rearranging the formula, moles of solute = Molarity (M) x volume of solution (in dm^3)

3. We have the volume of the solution in dm^3 (0.025 dm^3) and we need to find the moles of X. We can substitute the given values into the formula to find the molarity:

4.0 g of X = moles of X

Molarity (M) = moles of X / 0.025 dm^3

4. To find the moles of X, we need to know the molar mass of X. Once we have the molar mass, we can divide the mass of X by its molar mass to find the number of moles.

5. Suppose the molar mass of X is 100 g/mol (use the actual value if available). We divide the mass of X (4.0 g) by its molar mass (100 g/mol) to get 0.04 moles.

6. Plug the value of moles of X into the molarity formula:

Molarity (M) = 0.04 moles / 0.025 dm^3

7. Calculate the molarity:

Molarity (M) = 1.6 moles/dm^3

Therefore, the solubility of X is 1.6 moles/dm^3.