Posted by cindy on Wednesday, March 14, 2012 at 1:55pm.
The moment of inertia of weather vane with piece of clay is
I = I(vane) +mR^2 = 0.115+44.5•10^-3•(0.105)^2=
= 1.2•10^-2 kg • m2.
The torque due to the clay hitting is M=F•R
F•t=Δp=m•v, therefore F=m•v/t.
Then M=F•R=m•v•R/t.
From Newton’s 2 Law for rotation M=I• ε.
m•v•R/t =I•ε.
m•v•R/I= ε• t = ω
ω = m•v•R/I ==44.5•10^-3•18.5•0.105/1.2•10^-2= 7.21 rad•s
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