Saturday

April 19, 2014

April 19, 2014

Posted by **cindy** on Wednesday, March 14, 2012 at 1:36pm.

Points

Submissions Used

A baseball pitcher pivots his extended arm about his shoulder joint, applying a constant torque of 170 N · m for 0.15 s to his arm, which has a moment of inertia of 0.53 kg · m2.

(a) Find his arm's angular acceleration and final angular velocity, assuming it starts from rest.

angular acceleration

final angular velocity

(b) Find the final speed of the ball, relative to his shoulder, which is 0.76 m from the ball.

- PHYSICS -
**Elena**, Wednesday, March 14, 2012 at 1:51pmNewton’s 2 Law for rotation:

M=I• ε,

angular acceleration is

ε = M/I=170/0.53=320.8 rad/s^2

Final angular velocity (if initial velocity is zero) is

ω = εt = 320.8•0.15= 48.1 rad/s.

v= ωR = 48.1•0.76= 36.6 m/s

**Related Questions**

Physics - 24. 0/3 points All Submissions Notes Question: Walker2 3.P.015. ...

physics - A baseball pitcher can throw a baseball at a speed of 42 m/s. If the ...

Physics - A baseball pitcher can throw a baseball at a velocity of 44.5 m/s. If ...

Physics - A baseball pitcher can throw a baseball at a velocity of 44.5 m/s. If ...

physics - Question Part Points Submissions Used A bus slows down uniformly from ...

Physics - Now assume that the pitcher in Part D throws a 0.145-kg baseball ...

h.s physics - a baseball pitcher throws a baseball with a speed of 38m/s. ...

h.s. physics - a baseball pitcher throws a baseball with a speed of 38m/s. ...

physics help ! - a baseball pitcher throws a baseball with a speed of 38m/s. ...

calculus - Question Part Points Submissions Used What is the percentage ...