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A car traveling at 37 m/s breaks to a stop in 6.0 m and 3.5 s. What was the car’s acceleration? 

  • physics -

    For decelerated motion
    s= vt-at^2/2.

    a=2(vt-s)/t^2=2(37•3.5-6)/3.5^2=20.16 m/s^2

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