Posted by **chama** on Wednesday, March 14, 2012 at 11:08am.

Given the quadratic functionf(x)=x^2+(3k+1)x+k^2,find the value(s)of kif f(x)is a perfect square

- maths -
**Steve**, Wednesday, March 14, 2012 at 2:41pm
If x^2+(3k+1)x+k^2 is a perfect square, then

3k+1 = 2k

because (x+a)^2 = x^2 + 2ax + a^2

so, k=-1, and your polynomial is

x^2 -2x + 1 = (x-1)^2

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