Posted by **Michelle** on Tuesday, March 13, 2012 at 5:20pm.

An electric dipole comprised of two charges Q and -Q are separated by a distance of 3.0 cm. Assume Q = 2.0x10^-6 C and -Q = -2.0x10^-6 C.

Find the magnitude and direction of the electric field vector E and point P, which is 4.0 cm to the right of the center of -Q.

Find the value of the electric potential V and point P.

--To start, I know that E=k|q'|/r^2 but I am unsure of how to calculate the effect on P. I know for potential difference I calculate Vab = (k\d)(q1-q2)(1-(1/sqrrt of 2) which gave me 3.51x10^5 V, but I'm not sure if that's what they are asking me to calculate.

Any help is appreciated.

## Answer This Question

## Related Questions

- Chemistry - Two fixed charges, -4μC and -5μC, are separated by a ...
- physics - A dipole consists of two charges +q and -q, held apart by a rod of ...
- PHYSICS - how far apart are two point charges of 5.0x10^-6 C and 6.0x10^-6 C if ...
- Physics - Two point charges of magnitudes -6.25 nano coulomb and -12.5 nano ...
- gen. physics II - Two charges, +Q and ‑Q, are located two meters apart ...
- physics - Two particles are in a uniform electric field whose value is +4000 N/C...
- physics - Which of the following statements about electric field lines due to ...
- PHYSICS - 1. Why is an electric field considered to be a vector quantity? 2. ...
- Physics 221 - Two fixed charges -4.0 C and -5.0 C, are separated a certain ...
- Physics - We have a charge q = -0.6 x 10^-6 C at origin. And a vector r = (4 m, ...

More Related Questions