Posted by **jessica** on Tuesday, March 13, 2012 at 4:47pm.

How far (in meters) above the earth's surface will the acceleration of gravity be 27.0 % of what it is on the surface? can someone please just give me an equation to figure this out please I am lost

- physics -
**tchrwill**, Wednesday, March 14, 2012 at 10:47am
As we normally think of it, the static value of gravity on, or above the surface of a spherical body is directly proportional to the mass of the body and inversely proportional to the square of the distance from the center of the body and is defined by the expression g = GM/r^2 = µ/r^2 where GM = µ = the gravitational constant of the body (G = the Universal Gravitational Constant and M = the mass of the body) and r = the distance from the center of the body to the point in question.

With the earth's mean radius of 6378km and gravitational constant GM of 3.986365m^3/sec^2, the surface gravity g = GM/6378000^2 = 9.8m/sec^2. Therefore, the height above the earth's surface where g = .27(9.8) derives from r = sqrt[(GM/.27(9.8))/1000] - 6378.

## Answer This Question

## Related Questions

- physic - How far (in meters) above the earth's surface will the acceleration of ...
- Physics - How far above the surface of the Earth does an object have to be in ...
- Grade 12 Physics - A rocket ship is moving away from the earth after having been...
- Physics help please - The space shuttle orbits at a distance of 335 km above the...
- Physics - A satellite is orbiting the earth just above its surface. The ...
- Physics - For which of the following situations can the equation F = mg not be ...
- physics - 1. The acceleration due to gravity calculated this way works well for ...
- physics - 1. The acceleration due to gravity calculated this way works well for ...
- Physics - The acceleration due to gravity calculated this way works well for ...
- physics - A satellite is placed in orbit 100 km above the surface of the earth (...

More Related Questions