Friday

September 19, 2014

September 19, 2014

Posted by **jessica** on Tuesday, March 13, 2012 at 4:47pm.

- physics -
**tchrwill**, Wednesday, March 14, 2012 at 10:47amAs we normally think of it, the static value of gravity on, or above the surface of a spherical body is directly proportional to the mass of the body and inversely proportional to the square of the distance from the center of the body and is defined by the expression g = GM/r^2 = µ/r^2 where GM = µ = the gravitational constant of the body (G = the Universal Gravitational Constant and M = the mass of the body) and r = the distance from the center of the body to the point in question.

With the earth's mean radius of 6378km and gravitational constant GM of 3.986365m^3/sec^2, the surface gravity g = GM/6378000^2 = 9.8m/sec^2. Therefore, the height above the earth's surface where g = .27(9.8) derives from r = sqrt[(GM/.27(9.8))/1000] - 6378.

**Answer this Question**

**Related Questions**

physic - How far (in meters) above the earth's surface will the acceleration of ...

Physics help please - The space shuttle orbits at a distance of 335 km above the...

Physics - A satellite is orbiting the earth just above its surface. The ...

physics - A satellite is placed in orbit 100 km above the surface of the earth (...

Physics - How far above the surface of the Earth does an object have to be in ...

PHYSICS - AT WHAT DISTANCE ABOVE THE SURFACE OF THE EARTH IS THE ACCELERATION ...

Physics - The value of acceleration due to gravity (g) on a point 10,000 ...

Physics - At what distance above the surface of the earth is the acceleration ...

465465 - A satellite is orbiting the earth just above its surface. The ...

earth - A 5.0-kilogram sphere, starting from rest, falls freely 22 meters in 3.0...