Posted by Danielle on Tuesday, March 13, 2012 at 4:19pm.
and the answer at the back of this textbook says the acceleration should be 5.7 m/s^2.... but once again.. i dont know how they came up with this answer
and the answer at the back of this textbook says the acceleration should be 5.7 m/s^2.... but once again.. i dont know how they came up with this answer
well, look at m1. Force down the plane due to gravity: mgSin25
friction opposing motion: mg*mu*cos25
so the force on the m2 side (hanging mass) should be equal to the above sum.
47*9.8(sin25+.42cos25)=35*9.8+addedmass*9.8
your added mass should be the amount it takes to get it started.
Now, acceleration:
Net force= totalmass*a
(35+addedmass)9.8-47*9.8sin25-47*9.8*.19= (35+47+addedmass)a
solve for a.
For the force down the plane due to gravity, why isn't it just F=mg... and thank you so much for your help!
and which u do I use? should I use the static coefficient of friction since it isn't moving yet or the kinetic one since we want to know what will make the masses move?
forget about that last question haha
the formulas you gave didn't give the right answer, or at least not the same answer as they gave in the back of my textbook... any idea why this may be?
for some reason by multiplying the answer that I got for the "mass added" by 35kg, this gave me the answer at the back of the book
still doesn't help with finding the acceleration...
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