What is the mole fraction of each component of a gas mixture that contains sulfur trioxide at a pressure of 1.45 atm and sulfur dioxide at a pressure of 0.32 atms?
mol fraction A = partial pressure A/total pressure
To find the mole fraction of each component in a gas mixture, we need to know the partial pressures of the components and the total pressure of the mixture.
In this case, we have two components: sulfur trioxide (SO3) and sulfur dioxide (SO2), with partial pressures of 1.45 atm and 0.32 atm, respectively.
The mole fraction of a component is calculated by dividing its partial pressure by the total pressure of the mixture.
First, let's find the total pressure of the gas mixture by adding the partial pressures of the components:
Total pressure = Partial pressure of SO3 + Partial pressure of SO2
= 1.45 atm + 0.32 atm
= 1.77 atm
Now we can find the mole fraction of each component:
Mole fraction of SO3 = Partial pressure of SO3 / Total pressure
= 1.45 atm / 1.77 atm
= 0.819
Mole fraction of SO2 = Partial pressure of SO2 / Total pressure
= 0.32 atm / 1.77 atm
= 0.181
Therefore, the mole fraction of sulfur trioxide (SO3) is 0.819, and the mole fraction of sulfur dioxide (SO2) is 0.181.