Posted by **james** on Tuesday, March 13, 2012 at 3:01am.

The length of time that it takes for a pendulum to make one complete swing depends on the length of the pendulum. The time in seconds, T, is related to the length in metres, L, through the equation T=2π√ L/9.8

State the domain and range of this function. (1 mark)

Graph this function for pendulums up to 20m in length. (3 marks)

If you wanted to construct a pendulum in the Ontario Science Centre that takes exactly 10s to complete one swing, how long would it have to be (to the nearest millimetre)? (2 marks)

What would be the effect on the value of T if the pendulum were made twice as heavy? (1 mark)

Can you please answer all the question.

Please can you guys help with the graph.

- math -
**Damon**, Tuesday, March 13, 2012 at 6:51am
all positive L and ll positive T

I am not going to try to draw a graph here. Put in a few values for L say L = 0, 1, 5, 20, 30 and calculate T

10 = 2 pi sqrt (L/g)

1.5915 = sqrt(L/9.8)

L/9.8 = 2.533

L = 24.824

To the nearest millimeter makes no sense by he way because 9.8 is a very rough approximation for g

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